16 cups =1 gallon
1gal H2O=8.34 lbs. H20
8.34 lbs H20=3.78 kg H20
3.78kg H20=378g H20
378g H20 divided into 16 cups H20 -----> 23.62 gramsH20 in 1 cup +26.37g coffee cup =50 grams total weight
If evaporation of water vapor at a given relative humidty and temperature and barometric pressue is taken into the equation post 1 hour the weight of the water will be less. I leave this to our resident physics experts to calculate the amount of H20 lost to evaportion post 1 hour. And what will the final weight in grams would the water be? It is a bugger of a calculation. Any takers?
This is, indeed, a bugger of a calculation.
However, we are lucky because rate of water evaporation isn't determined using weight. It seems like taking Arizona as a reasonable examine would do, where a general evaporation rate of a third of an inch per day is estimated, which would mean a week or so.
Since I don't think we have a volunteer that wants to stand around looking silly, you can also just leave a glass of water somewhere and see.
Btw, without mucking about too much with determining the surface area of a paper cup, I'd say about 1.4 grams per hour in evaporation without heating...
This message has been edited by Melchior, 07-20-2004 11:30 PM