16 cups =1 gallon
1gal H2O=8.34 lbs. H20
8.34 lbs H20=3.78 kg H20
3.78kg H20=378g H20
378g H20 divided into 16 cups H20 -----> 23.62 gramsH20 in 1 cup +26.37g coffee cup =50 grams total weight
If evaporation of water vapor at a given relative humidty and temperature and barometric pressue is taken into the equation post 1 hour the weight of the water will be less. I leave this to our resident physics experts to calculate the amount of H20 lost to evaportion post 1 hour. And what will the final weight in grams would the water be? It is a bugger of a calculation. Any takers?
"One is punished most for ones virtues" Fredrick Neitzche