Simple but fun math problem

I heard this on a podcast, I won't say which one in order to discourage people from looking up the answer.Place three digits, 2, 7 and one other, in an expression that equals 8. You can use +, -, *, / and exponentiation. Decimal points and parentheses may be used freely, but each digit may only appear once in the expression. Do this nine times where the remaining digit is 1 through 9. When you're done you'll have 9 expressions, each consisting of only three digits (2, 7 and the remaining digit of 1 through 9) and all equal to 8.For example, when the third digit is 1, the expression is: Now find the remaining 8 expressions.--Percy

One easy way to hide things is to use this approach: People can click on "peek" to see the hidden text.It looks like you've provided an additional solution for 1, three solutions for 3 (one of which is incorrect), two solutions for 9, and no solutions for 4, 5, 7 or 8.--Percy

Just so people realize what WoundedKing is doing, he's filling in the answers in the blank space as he figures them out.Edited by Percy, : Clicked too soon.

Dots are good, and be devisive.--PercyEdited by Percy, : Wrong hint.

Wounded King seems to have all but 5, 7 and 8. I don't know what a "..." operator is, but it isn't one of the operators listed for this problem.Discreet Label claims to have all but 8 and 9.Zawinul found that 0 also has an answer, he has 8, and he claims all the rest but 5 and 7.Modulus has all but 7.I didn't intend my hints to be misleading, but I didn't want to give away the answers, either. Apologies if they've sent anyone off in the wrong direction.--PercyEdited by Percy, : Update summary.

Yeah, I figured that out a few minutes later and edited my post.--Percy