Discontinuing research about ID

reIn other words, "no" -- because you just don't include them in your pattern ... that data is ignored.That's like counting cars that pass on the street, and not starting until a red car appears ...Full quote from Message 117: So you only start the "pattern" when a person appears. In other words, "yes" the first element is "a person appears" ... Thanks, I do now begin to see a pattern with this clarification. The way I see it now is that the pattern is this:Event 1: appearance of ∈ {P.Pi, P.Ri, P.Ya}, singly and/or with multiple interactions between them,
Event 2: appearance of ∈ {P.LF}
Event 3: appearance of ∈ {P.Wo, P.Tr}, singly and/or with multiple interactions between them,
Event 4: appearance of ∈ {P.Da}
Event 5" appearance of ∈ {PLF, P.Ya}, singly and/or with multiple interactions between them,Is there more, or is this the total "pattern" you have detected?So am I correct that each of the following sequences of appearances would fit this "pattern" ...

1. P.Pi - P.LF - P.Wo - P.Da - P.LF,
2. P.Pi - P.LF - P.Wo - P.Da - P.Ya,
3. P.Pi - P.LF - P.Wo - P.Da - P.LF - P.Ya,
4. P.Pi - P.LF - P.Wo - P.Da - P.Ya - P.LF,
5. P.Pi - P.LF - P.Tr - P.Da - P.LF,
6. P.Pi - P.LF - P.Tr - P.Da - P.Ya,
7. P.Pi - P.LF - P.Tr - P.Da - P.LF - P.Ya,
8. P.Pi - P.LF - P.Tr - P.Da - P.Ya - P.LF,
9. P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF
10. P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya
11. P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
12. P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
13. P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF,
14. P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
15. P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
16. P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
17. P.Ri - P.LF - P.Wo - P.Da - P.LF,
18. P.Ri - P.LF - P.Wo - P.Da - P.Ya,
19. P.Ri - P.LF - P.Wo - P.Da - P.LF - P.Ya,
20. P.Ri - P.LF - P.Wo - P.Da - P.Ya - P.LF,
21. P.Ri - P.LF - P.Tr - P.Da - P.LF,
22. P.Ri - P.LF - P.Tr - P.Da - P.Ya,
23. P.Ri - P.LF - P.Tr - P.Da - P.LF - P.Ya,
24. P.Ri - P.LF - P.Tr - P.Da - P.Ya - P.LF,
25. P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF
26. P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya
27. P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
28. P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
29. P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF,
30. P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
31. P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
32. P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
33. P.Ya - P.LF - P.Wo - P.Da - P.LF,
34. P.Ya - P.LF - P.Wo - P.Da - P.Ya,
35. P.Ya - P.LF - P.Wo - P.Da - P.LF - P.Ya,
36. P.Ya - P.LF - P.Wo - P.Da - P.Ya - P.LF,
37. P.Ya - P.LF - P.Tr - P.Da - P.LF,
38. P.Ya - P.LF - P.Tr - P.Da - P.Ya,
39. P.Ya - P.LF - P.Tr - P.Da - P.LF - P.Ya,
40. P.Ya - P.LF - P.Tr - P.Da - P.Ya - P.LF,
41. P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF
42. P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya
43. P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
44. P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
45. P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF,
46. P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
47. P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
48. P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
49. P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.LF,
50. P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.Ya,
51. P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.LF - P.Ya,
52. P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.Ya - P.LF,
53. P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.LF,
54. P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.Ya,
55. P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.LF - P.Ya,
56. P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.Ya - P.LF,
57. P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF
58. P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya
59. P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
60. P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
61. P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF,
62. P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
63. P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
64. P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
65. P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.LF,
66. P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.Ya,
67. P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.LF - P.Ya,
68. P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.Ya - P.LF,
69. P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.LF,
70. P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.Ya,
71. P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.LF - P.Ya,
72. P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.Ya - P.LF,
73. P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF
74. P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya
75. P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
76. P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
77. P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF,
78. P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
79. P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
80. P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
81. P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.LF,
82. P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.Ya,
83. P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.LF - P.Ya,
84. P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.Ya - P.LF,
85. P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.LF,
86. P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.Ya,
87. P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.LF - P.Ya,
88. P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.Ya - P.LF,
89. P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF
90. P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya
91. P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
92. P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
93. P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF,
94. P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
95. P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
96. P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
    ​
97. P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.LF,
98. P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.Ya,
99. P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.LF - P.Ya,
100. P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.Ya - P.LF,
101. P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.LF,
102. P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.Ya,
103. P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.LF - P.Ya,
104. P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.Ya - P.LF,
105. P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF
106. P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya
107. P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
108. P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
109. P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF,
110. P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
111. P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
112. P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
113. P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.LF,
114. P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.Ya,
115. P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.LF - P.Ya,
116. P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.Ya - P.LF,
117. P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.LF,
118. P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.Ya,
119. P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.LF - P.Ya,
120. P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.Ya - P.LF,
121. P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF
122. P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya
123. P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
124. P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
125. P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF,
126. P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
127. P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
128. P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
129. P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.LF,
130. P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.Ya,
131. P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.LF - P.Ya,
132. P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.Ya - P.LF,
133. P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.LF,
134. P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.Ya,
135. P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.LF - P.Ya,
136. P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.Ya - P.LF,
137. P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF
138. P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya
139. P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
140. P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
141. P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF,
142. P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
143. P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
144. P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
145. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.LF,
146. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.Ya,
147. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.LF - P.Ya,
148. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Da - P.Ya - P.LF,
149. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.LF,
150. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.Ya,
151. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.LF - P.Ya,
152. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Da - P.Ya - P.LF,
153. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF
154. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya
155. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
156. P.Pi - P.Ri - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
157. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF,
158. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
159. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
160. P.Pi - P.Ri - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
161. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.LF,
162. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.Ya,
163. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.LF - P.Ya,
164. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Da - P.Ya - P.LF,
165. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.LF,
166. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.Ya,
167. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.LF - P.Ya,
168. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Da - P.Ya - P.LF,
169. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF
170. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya
171. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
172. P.Pi - P.Ya - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
173. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF,
174. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
175. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
176. P.Pi - P.Ya - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
177. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.LF,
178. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.Ya,
179. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.LF - P.Ya,
180. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Da - P.Ya - P.LF,
181. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.LF,
182. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.Ya,
183. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.LF - P.Ya,
184. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Da - P.Ya - P.LF,
185. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF
186. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya
187. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
188. P.Ri - P.Pi - P.Ya - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
189. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF,
190. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
191. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
192. P.Ri - P.Pi - P.Ya - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
193. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.LF,
194. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.Ya,
195. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.LF - P.Ya,
196. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Da - P.Ya - P.LF,
197. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.LF,
198. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.Ya,
199. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.LF - P.Ya,
200. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Da - P.Ya - P.LF,
201. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF
202. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya
203. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
204. P.Ri - P.Ya - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
205. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF,
206. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
207. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
208. P.Ri - P.Ya - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
209. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.LF,
210. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.Ya,
211. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.LF - P.Ya,
212. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Da - P.Ya - P.LF,
213. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.LF,
214. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.Ya,
215. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.LF - P.Ya,
216. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Da - P.Ya - P.LF,
217. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF
218. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya
219. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
220. P.Ya - P.Ri - P.Pi - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
221. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF,
222. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
223. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
224. P.Ya - P.Ri - P.Pi - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,
     ​
225. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.LF,
226. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.Ya,
227. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.LF - P.Ya,
228. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Da - P.Ya - P.LF,
229. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.LF,
230. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.Ya,
231. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.LF - P.Ya,
232. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Da - P.Ya - P.LF,
233. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF
234. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya
235. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.LF - P.Ya
236. P.Ya - P.Pi - P.Ri - P.LF - P.Wo - P.Tr - P.Da - P.Ya - P.LF
237. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF,
238. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya,
239. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.LF - P.Ya,
240. P.Ya - P.Pi - P.Ri - P.LF - P.Tr - P.Wo - P.Da - P.Ya - P.LF,

... and that this list is not complete? (note that two of your examples are not included: and that this would expand the number of templates by a factor of 2 or 3 (or more)Please confirm or clarify.EnjoyEdited by RAZD, : added variation to list that were missed -- there are others I have omitted for brevity ... :rolleyes"

Slowly getting there Let's go back a bit and stick to just event 1 for now. Excellent. So there are 19 elements included in ∈ {P.Al, P.BW, P.Da, P.LF, P.Pi, P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7, M13}, and ∈ {P.Al-, P.BW+, P.Tr+, P.WeC-}, that can occur singly and/or with multiple interactions between them, ...... and the number of possible permutations for event 1 are at least: ... because multiple appearances of elements are not included in this calculation.Would you agree that there is a high probability that event #1 occurs?Can you tell me how many elements do not qualify for event #1? ....... or is this the point in the "teaser" that you initialize\start your "pattern" (in which case the probability of it occurring in the "pattern" is 1.0 by definition) -- the "red car" used to start your count of passing cars.EnjoyEdited by RAZD, : ..

Well I don't know if I am more confused rather than less confused by your further explanations ... Now I'll admit I was initially confused by your "pattern" column headers, as I thought you were referring to episodes rather than to a sequence of "events" ...So am I correct now, to think that everything listed in each column can occur either together or in any series composed of just those elements in the columns?ie -- that you do not have sub-events within these "events" yes?This could also be a problem others are having with understanding just what it is you mean by the pattern, so I would like some specific clarification here before proceeding. I fail to see the need for this distinction when the "event" includes a mix of appearance order and sequences that can all occur up to the moment that the next event begins.In addition I now have to ask if you mean ... ... that those are two groups that "appear at the same moment together"? or are you mixing up your symbolism to cause confusion? (cause I guarantee that you have caused confusion).Enjoy

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But people do tend to get snippy when you claim that they said something that wasn't said.For the record, I too have stated that I see no support at all in the paper for the assertion that ID is involved, due to the logially incomplete (to put it kindly) argument (actually invalid is more to the point), and that I saw absolutely no connection to any specific god other than wishful thinking. This: was sarcasm regarding your assumption of a triune god/s. (a combination of "when pigs fly" with "the three little pigs" and "invisible unicorns") Okay, that helps understand what that horrid table was all about. Let me see if I can summarize it in english -- events occur in a sequence of events, one after the other as follows:

Event #1:Fifteen (15) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, P.LF, P.Pi,P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7. M13.

​

then

​

Event #2: Ten (10) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.BeC, P.BW, P.Da,, P.LF, P.Ri, P.WeC, P.Ya, M4, M5.

​

then

​

Event #3: Fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.BW, P.Da, P.En, P.Pi, P.Ri, P.Tr, P.Wo, P.WSA, P.Ya, M1, M3, M5, M6.

​

then

​

Event #4: Four (4) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.Wo, M4, M10.

​

then

​

Event #5: fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Wo, P.Ya, M2, M4, M5, M7, M10.

​

then

​

Event #6: seven (7) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.Pi, P.Ri, P.Tr, P.Wo, M1, M6.

​

then

​

Event #7: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M2, M4, M7, M14.

​

then

​

Event #8: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, M1, M4, M5, M6, M10, M13.

​

then

​

Event #9: seventeen (17) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1., P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M1, M2, M4, M7, M11, M14.

​

then

​

Event #10: six (6) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.LF, P.Pi, P.Wo, P.WSA, P.Ya.

​

then

​

Event #11: eleven (11) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.En, P.LF, P.Pi, P.Ri, P.WeC, P.Wo, P.WSA, M1, M6, M7.

​

then

​

Event #12: eleven (11) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Tr, P.Ya, M2, M10.

​

then

​

Event #13: fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, M1, M5, M6, M7.

​

then

​

Event #14: eighteen (18) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.BeC, P.BW, P.Da, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M1, M2, M3, M6, M7, M13.

​

and finally

​

Event #15: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.A1, P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M4, M12, M14.

Am I correct in thinking that none of these "events" can be omitted or put in a different order without breaking the "pattern"? Any sub-part of the listed "events" that would fit, from each single person being a different sub-event, for instance. That is confusing, you should use something else, like |P.Ri, P.Tr| to denote simultaneous appearances ... if that is actually necessary given that either can appear before the other in the same event. I put it down to extraneous information, just as the + and - designations do not appear to add any real significance to the purported pattere. Yes, you said that P.Ri could not be in event #1 and then listed him as being in event #1. Again I think you are being inconsistent and that is causing confusion and giving the impression that you don't really know what you are talking about. Please simplify and clarify as much as possible..If I am not correct on the "pattern" as I have listed it then please correct it.EnjoyEdited by RAZD, : ..

So the corrected "Pattern" would be:

• Event #1:Fifteen (15) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, P.LF, P.Pi,P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7. M13.
  ​
  then
  ​
• Event #2: Ten (10) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.BeC, P.BW, P.Da,, P.LF, P.Ri, P.WeC, P.Ya, M4, M5.
  ​
  then
  ​
• Event #3: Fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.BW, P.Da, P.En, P.Pi, P.Ri, P.Tr, P.Wo, P.WSA, P.Ya, M1, M3, M5, M6.
  ​
  then
  ​
  • OPTIONAL:
    ​
  • Event #4: Four (4) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.Wo, M4, M10.
    ​
    then
    ​
  • Event #5: fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Wo, P.Ya, M2, M4, M5, M7, M10 M14.
    ​
    then
    ​
  • Event #6: seven (7) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.Pi, P.Ri, P.Tr, P.Wo, M1, M6.
    ​
    then
    ​
  • Event #7: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M2, M4, M7, M14.
    ​
    then
    ​
  • Event #8: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, M1, M4, M5, M6, M10, M13.
  ​
  then
  ​
• Event #9: seventeen (17) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI., P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M1, M2, M4, M7, M11, M14.
  ​
  then
  ​
• OPTIONAL: Event #10: six (6) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.LF, P.Pi, P.Wo, P.WSA, P.Ya.
  ​
  then
  ​
• OPTIONAL: Event #11: eleven (11) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.En, P.LF, P.Pi, P.Ri, P.WeC, P.Wo, P.WSA, M1, M6, M7.
  ​
  then
  ​
• Event #12: eleven (11) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Tr, P.Ya, M2, M10.
  ​
  then
  ​
• Event #13: fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, M1, M5, M6, M7.
  ​
  then
  ​
• Event #14: eighteen (18) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.BeC, P.BW, P.Da, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M1, M2, M3, M6, M7, M13.
  ​
  and finally
  ​
• Event #15: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.AI, P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M4, M12, M14.

Only optional events 10 and/or 11 and/or group {4,5,6,7,8} can be omitted, the order of events cannot be changed.Is this correct? As I had conjectured. EnjoyEdited by RAZD, : ...

P.Al and P.AI look the same with the font on my computer, I did not find M12 listed at E12 ...... as a side note I find your nomenclature overly complex and clunky to use ... this could have been just "PA" -- symbols are just place holders. For this reason I have intentionally omitted the + and - symbols because I don't see that they add anything at this point.So now the corrected corrected "Pattern" (less +'s and -'s ... which YOU can add if you feel it is necessary) would be:

• Event #1:Fifteen (15) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, P.LF, P.Pi,P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7. M13.
  ​
  then
  ​
• Event #2: Eight (8) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BeC, P.BW, P.Da, P.LF, P.Ri, P.WeC, P.Ya, M4, M5.
  ​
  then
  ​
• Event #3: Fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, P.En, P.Pi, P.Ri, P.Tr, P.Wo, P.WSA, P.Ya, M1, M3, M5, M6.
  ​
  then
  ​
  • OPTIONAL:
    ​
  • Event #4: Four (4) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.Wo, M4, M10.
    ​
    then
    ​
  • Event #5: fourteen (14) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Wo, P.Ya, M2, M4, M5, M7, M10 M14.
    ​
    then
    ​
  • Event #6: five (5) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.Pi, P.Ri, P.Tr, P.Wo, M1, M6.
    ​
    then
    ​
  • Event #7: sixteen (16) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M2, M4, M7, M14.
    ​
    then
    ​
  • Event #8: nine (9) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, >P.En,P.WeC, P.Wo, M1, M4, M5, M6, M10, M13.
  ​
  then
  ​
• Event #9: eighteen (18) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al., P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.Ya, M1, M2, M4, M7, M11, M14.
  ​
  then
  ​
• OPTIONAL: Event #10: six (6) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.LF, P.Pi, P.Wo, P.WSA, P.Ya.
  ​
  then
  ​
• OPTIONAL: Event #11: nine (9) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Da, P.En, P.LF, P.Pi, P.Ri, P.WeC, P.Wo, P.WSA, M1, M6, M7.
  ​
  then
  ​
• Event #12: nine (9) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al. P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Tr, P.Ya, M2, M10.
  ​
  then
  ​
• Event #13: ten (10) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, M1, M5, M6, M7.
  ​
  then
  ​
• Event #14: eighteen (18) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BeC, P.BW, P.Da, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M1, M2, M3, M6, M7, M13.
  ​
  and finally
  ​
• Event #15: fifteen (15) elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BeC, P.BW, P.Da, P.En, P.LF, P.Pi, P.Ri, P.Tr, P.WeC, P.Wo, P.WSA, P.Ya, M4, M12, M14.

Only optional events 10 and/or 11 and/or group {4,5,6,7,8} can be omitted, the order of events cannot be changed.Is this NOW correct?If it is not then please make the corrections yourself (you can copy what I have done by using the "peek" function, either the |PEEK| button at the bottom of the post or "peek mode" (Normal: Peek Mode:) when in the reply window).In the meantime I will proceed on the basis of this being correct.Enjoy.

So we now have your "pattern" correctly spelled out in simple english ... that wasn't too bad, was it?So we have Event #1 with 15 possible elements, which if they occur singly or in combination with other elements of this event means (1x15!)+ (15x14!)+ (105x13!)+ (455x12!)+ (1365x11!)+ (3003x10!)+ (5005x9!)+ (6435x8!)+ (6435x7!)+ (5005x6!)+ (3003x5!)+ (1365x4!)+ (455x3!)+ (105x2!)+ (15x1!) = = 3.554627472075E+12 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #2 with 8 possible elements, which if they occur singly or in combination with other elements of this event means (1x8!)+ (8x7!)+ (28x6!)+ (56x5!)+ (70x4!)+ (56x3!)+ (28x2!)+ (8x1!) = 1.09600E+5 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #3 with 14 possible elements, which if they occur singly or in combination with other elements of this event means (1x14!)+ (14x13!)+ (91x12!)+ (364x11!)+ (1001x10!)+ (2002x9!)+ (3003x8!)+ (3432x7!)+ (3003x6!)+ (2002x5!)+ (1001x4!)+ (364x3!)+ (91x2!)+ (14x1!) = 2.36975164804E+11 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #4 with 4 possible elements, which if they occur singly or in combination with other elements of this event means (1x4!)+ (4x3!)+ (6x2!)+ (4x1!) = 6.4e+1 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #5 with 14 possible elements, which if they occur singly or in combination with other elements of this event means (1x14!)+ (14x13!)+ (91x12!)+ (364x11!)+ (1001x10!)+ (2002x9!)+ (3003x8!)+ (3432x7!)+ (3003x6!)+ (2002x5!)+ (1001x4!)+ (364x3!)+ (91x2!)+ (14x1!) = 2.36975164804E+11 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #6 with 5 possible elements, which if they occur singly or in combination with other elements of this event means (1x5!)+ (5x4!)+ (10x3!)+ (10x2!)+ (5x1!)
= 3.25E+2 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #7 with 16 possible elements, which if they occur singly or in combination with other elements of this event means (1x16!)+ (16x15!)+ (120x14!)+ (560x13!)+ (1820x12!)+ (4368x11!)+ (8008x10!)+ (11440x9!)+ (12870x8!)+ (11440x7!)+ (8008x6!)+ (4368x5!)+ (1820x4!)+ (560x3!)+ (120x2!)+ (16x1!) = 1.74034561032844E+16 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #8 with 9 possible elements, which if they occur singly or in combination with other elements of this event means (1x9!)+ (9x8!)+ (36x7!)+ (84x6!)+ (126x5!)+ (126x4!)+ (84x3!)+ (36x2!)+ (9x1!)
= 9.86409E+5 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #9 with 18 possible elements, which if they occur singly or in combination with other elements of this event means (1x18!)+ (18x17!)+ (153x16!)+ (816x15!)+ (3060x14!)+ (8568x13!)+ (18564x12!)+ (31824x11!)+ (43758x10!)+ (48620x9!)+ (43758x8!)+ (31824x7!)+ (18564x6!)+ (8568x5!)+ (3060x4!)+ (816x3!) (153x2!) (18x1!) = 1.7403456103284400e+16 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #10 with 6 possible elements, which if they occur singly or in combination with other elements of this event means (1x6!)+ (6x5!)+ (15x4!)+ (20x3!)+ (15x2!)+ (6x1!) = 1.956E+3 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #11 with 9 possible elements, which if they occur singly or in combination with other elements of this event means (1x9!)+ (9x8!)+ (36x7!)+ (84x6!)+ (126x5!)+ (126x4!)+ (84x3!)+ (36x2!)+ (9x1!) = 9.86409E+5 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #12 with 9 possible elements, which if they occur singly or in combination with other elements of this event means (1x9!)+ (9x8!)+ (36x7!)+ (84x6!)+ (126x5!)+ (126x4!)+ (84x3!)+ (36x2!)+ (9x1!) = 9.86409E+5 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #13 with 10 possible elements, which if they occur singly or in combination with other elements of this event means (1x10!)+ (10x9!)+ (45x8!)+ (120x7!)+ (210x6!)+ (252x5!)+ (210x4!)+ (120x3!)+ (45x2!)+ (10x1!) = 9.8641006 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #14 with 18 possible elements, which if they occur singly or in combination with other elements of this event means (1x18!)+ (18x17!)+ (153x16!)+ (816x15!)+ (3060x14!)+ (8568x13!)+ (18564x12!)+ (31824x11!)+ (43758x10!)+ (48620x9!)+ (43758x8!)+ (31824x7!)+ (18564x6!)+ (8568x5!)+ (3060x4!)+ (816x3!) (153x2!) (18x1!) = 1.74034561032844E+016 possible permutations (variations) of elements for this event, where no element repeats in this event;... Event #15 with 15 possible elements, which if they occur singly or in combination with other elements of this event means (1x15!)+ (15x14!)+ (105x13!)+ (455x12!)+ (1365x11!)+ (3003x10!)+ (5005x9!)+ (6435x8!)+ (6435x7!)+ (5005x6!)+ (3003x5!)+ (1365x4!)+ (455x3!)+ (105x2!)+ (15x1!) = 3.554627472075E+12 possible permutations (variations) of elements for this event, where no element repeats in this event;AND thus a first order approximation of the total possible permutation\variations allowed to fit this "pattern" is 3.55E+12 x 1.10E+5 x 2.37E+11 x 6.40E+1 x 2.37E+11 x 3.25E+2 x 5.69E+13 x 9.86E+5 x 1.74E+16 x 1.96E+3 x 9.86E+5 x 9.86E+5 x 9.86E+6 x 1.74E+16 x 3.55E+12 = 5.16E+131 permutations (variations) of the "pattern" for all events, where no element repeats in any one event.IF, as you allow, elements can repeat within an "event" then the number of possible permutations\variations explodes exponentially, for instance in event #4 you have 4 elements and if each one repeats within the event we now have 8 elements and 109,600 possible permutations instead of 64 (ie - over a 1700 fold increase), and if each one can repeat a third time that makes 12 elements and 1,302,061,344 possible permutations (ie - over a 20,000,000 fold increase) ... and each of the other "events" would grow in similar manner, resulting in virtually infinite possibilities, certainly as far as the episodes being written are concerned. Without knowing the number of repetitions the final calculation is indeterminant, and extremely divergent rather than trending to a final value. The similar calculation for the number of non-possibilities is equally indeterminate and widely variable from the information given. That means that your probability calculation must be flawed: you have to know the possibilities before you can derive the probabilities, and your result is either a mistake or an artifact of an incomplete analysis.That's problem #1 with your concept.No ID, no triune god/s involved, just human error.Next, if you want to continue, we can get into the issue of replicating your work, especially why your elements are grouped the way they are: why would/should I conclude that these all are the same pattern being followed? ... when each of these "sample episodes" has different elements at each event; these "sample episodes" are different lengths, and no single character appears more than once in any of these episodes?It seems to me on a first level evaluation, that these are in reality 5 completely different patterns and that not one of them fits the other "sample episodes" even though they all "comply" with your "pattern" ...What can I do to make these all fit a single pattern without arbitrarily grouping elements? What is your method for doing this? What are the reasons for your groupings?Enjoy

Thanks. For the peanut gallery "fieldset" refers to the html code I used to draw the box around the white backgrounded area that the "pattern" is described on. Gives it a nice embossed appearance. So can I assume that you consider P.WeC- ≠ P.WeC ≠ P.WeC+ ... ie - that these are actually different elements? Can only people be +/- not M's? I had also considered the sequence P.Pi, p.pi, P.Pi, where P.Pi would be current and p.pi would be a "flashback" to when he was borg.This means that probability cannot properly be calculated. Just because you can plunk values into a function does not mean that you are using the function properly. We can come back to this later if you want. For what it's worth I don't think anyone here thinks this calculation is a valid result. Curiously, I am not quite convinced this is true. Let's review the transition between Event #1 and Event #2, and see if we can tease some more information out of you on how your "pattern" works: As you have acknowledged each of these elements can repeat ad nauseum, so the question becomes when does event #1 end and event #2 begin? Of these elements P.Al, P.LF, M5, are in event #1 and thus their repetition would not initiate event #2, ... nor would their continued presence invalidate event #2 ...... so event #2 would have to be initiated by the observation "either singly or in combinations and all with possible repeated appearances" of P.BeC, P.Ri, P.WeC (≠P.WeC-), P.Ya, M4, P.BW- (≠P.BW), P.Da- (≠P.Da), ...... and of these, three elements are obvious transitions: P.WeC- → P.WeC, P.BW → P.BW-, and P.Da → P.Da-, ... these would be single occurances but any 1, 2, or 3 of these could occur?... and finally, elements that have to cease being present\observed for Event #2 to start (if they were involved in Event #1) are: P.Pi, P.Tr, P.Wo, P.WSA, M1, M2, M6, M7, M13, P.Al-, P.BW+, P.Tr+.Would that be correct?Can there be a period of overlap\transition between events when elements unique to the two events appear together?So there would appear to be a clear signal possible for when one event ends and the next begins, that would include:

1. disappearance of any elements that are not observed in the next event,
2. appearance of any of the elements of the next event that are not observed in the previous event, and
3. appearance of any element not in either event.

The first two are needed for the transition from one event to the next, the third means the pattern is broken.Because it only takes one observation\appearance of any invalid element (type 3), it would seem to me possible to compile a list of these invalidating elements, and that they would make a finite list.Enjoy

Thanks for the clarification, but I still need some help. So P.WeC- and P.WeC+ are not appearances -- does the person (P.WeC in this case) need to be present for +/- to occur? Can you have P.WeC without it being * P.WeC, P.WeC- or P.WeC+ ? I'm just trying to understand your marking system. So I'm thinking that it will be more valuable to discuss what cannot be in Event #n and the transition from Event #n to Event #n+1. This would start with a full listing of all the elements. So we have 13 people with three flavors +,* and -, and 14 M's (please check this, it seemed to me that there were some gaps: I see M1, M2, M3, M4, M5, M6, M7, M10, M11, M12, M13, and M14 -- M8 and M9 seem to be missing from the "pattern" table 4 Message 1 pdf of paper linkSo there are only 12 different "marks" in the pattern. This would make a total of 13*3 + 12 = 51 different elements.Would I be correct in thinking that anything not covered by this list is ignored in the "pattern" derivation and applications? I plan to, but as an initial comment you say that the calculation is based on the observed incidents rather than on an accounting of the possibilities, yes?If I throw a di 10 times and only get numbers between 1 and 3, can I calculate with confidence the probability of what the next throw will be? Would you calculate that probability based on the number of 1's the number of 2's and the number of 3's in those 10 throws to predict the next toss? Certainly I can take the results of those 10 throws and put them through standard probability calculations while ignoring possibilities that did not occur during the data gathering phase, yes?If we assume that we don't know what shape the di was -- Tetrahedron (four faces), Cube or hexahedron (six faces), Octahedron (eight faces), Dodecahedron (twelve faces), Icosahedron (twenty faces) -- then the only evidence we have for the possibilities is what is observed during the data gathering phase, yes?But we KNOW from this simple example that calculating presumed probabilities based on the observed results will not give us an accurate calculation of the probability for the next throw or it's result.Essentially you are assuming that the three observed results are the only possibilities. Nor do we know if the di was weighted so we are assuming that the results are not biased.Enjoy

The question you did not answer was why\how should I conclude that these three hypothetical episodes should be part of the same pattern: and how do I correct D and E so they fit the pattern?Enjoy

So we have *P.Da, (observed) P.Da-, (adversly affected) *P.Ri, (observed) *P.Da, (observed) P.Da+, (positively affected) *P.Ri, (observed) *P.WeC, (observed) P.WeC+ (positively affected)ie no, P.WeC- and P.WeC+ are not appearances, but yes the person (P.WeC in this case) need to be present\observed for +/- to occur, is this correct?Thus we could define elements as

1. (*P.(A), not affected) = element 1
2. *P.(A) becomes positively affected: P.(A)+ = element 2
3. *P.(A) becomes negatively affected: P.(A)- = element 3
4. (*P.(B), not affected) = element 4
5. *P.(B) becomes positively affected: P.(A)+ = element 5
6. *P.(B) becomes negatively affected: P.(A)- = element 6
   etc

... and 13 people would generate 39 different elements.Because of the way you define appearance\observation as including being named, it seems that it would not be possible to affect a person without identifying the person being affected and counting that as an appearance\observation, yes? Plus the 39 people elements would make a total of 51 elements. So we could add #52: Something Else not included in the other 51, to cover this otherwise ignored element. Thank you, that would then give 5 hypothetical episodes: But I was looking to make 5 "episodes" that

1. don't repeat any elements in other "episodes" for the same event
   (D and E now both have P.Ya in event #2 and B and E now both have M4 in event #15
   and
2. don't repeat any elements within that episode
   (D has P.Ya repeated 3 times and M6 twice)

Would you be able to change that so each hypothetical episode matches your "pattern" and is unique? I'm not sure you are understanding the question: I'm trying to determine how you developed your groups so that I could reproduce your work. The reason that I wanted 5 hypothetical episodes with no repeated element across the event levels or within each episode is so you can describe, and I can understand, how they get grouped during analysis.EnjoyEdited by RAZD, : "presenobserved" to present\observedEdited by RAZD, : m6 in red

If it is clear who they are, then are they not identified\observed\appeared? I suppose they could be in the immediate previous event for the reference to work.The only way I can see having a P.(A)+ or P.(A)- is for them to be preceded by the appearance of P.(A) ... and I think this is what NoNukes was driving at: P.(A)+ or P.(A)- are not appearances and they have to be preceded by the appearance of P.(A): *P.(A) ... either in the same event (n) or the immediately previous event (n-1) (so "it is clear who "he" or "she" is") Curiously, I was trying to isolate the elements so that they are not dependent on another element preceding it, and that was why I was grouping the dependent elements with their precedents and redefining that as a distinct elements within the events to avoid that problem:

1. P.(A) appears and is not affected: *P.(A)&‘ = element 1
2. P.(A) appears and becomes positively affected: *P.P(A)&P.(A)+ = element 2
3. P.(A) appears and becomes negatively affected: *P.P(A)&P.(A)- = element 3
4. P.(B) appears and is not affected: *P.(B)&‘ = element 4
5. P.(B) appears and becomes positively affected: *P.P(B)&P.(B)+ = element 5
6. P.(B) appears and becomes negatively affected: *P.P(B)&P.(B)- = element 6
   etc

In this system any reference to "he" or "she" is counted as an appearance (which is valid because we know who the "he" or "she" is in order to assign the +/- effect).An alternative would be to change the +/- aspects to generic marks M+ and M- that don't depend on specific previous appearances of specific people ... and with this system your previous example would be rendered asP.Da: "I feel so sick"
P.Ri: "Does this medicine help?"
P.Da: "Yes, it helps a lot. I feel better now"
P.Ri: "I will go to P.WeC. This medicine will also heal him."becomes: *P.Da, M-, *P.Ri, *P.Da, M+, *P.Ri, *P.WeC, M+My reason for this is that it is necessary to properly calculate independent possibilities and probabilities. And I think this approach would be more consistent with your other "mark" elements. Again if we counted *P.(A) as "one or more appearances of P.(A)" within an event then it simplifies things and the example would become:*P.Da, M-, *P.Ri, M+, *P.WeC, M+Or verbally: Data appears, bad happens Riker appears, good happens, Wesley appears, good happens.And this would mean

1. each "element" is independent of any other element
2. the appearance of an element within an event is independent of the number of appearances
3. there would be 13 people elements and 14 mark elements for a total of 27 elements
4. and adding one for "something else" (MSE) would cover any ignored parts and bring the total elements to 28.

With this system all possibilities are described and we can then calculate probabilities.Enjoy

What are they? Let's take E1->E2 first. From Message 166 we have: E1: Elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BW, P.Da, P.LF, P.Pi,P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7, M13, P.Al-, P.BW+, P.Tr+, P.WeC-. Caveat: +/- cannot be observed without * appearance of individual.In revised system A (per Message 187) this would be written: E1: Elements are observed, either singly or in combinations and all with possible repeated appearances -- {*P.Al&‘}, {*P.Al&P.Al-}, {*P.BW&‘}, {*P.BW&P.BW+}, {*P.Da&‘}, {*P.LF&‘}, {*P.Pi&‘},{*P.Tr&‘}, {*P.Tr&P.Tr+}, {*P.WeC&‘}, {*P.WeC&P.WeC-}, {*P.Wo&‘}, {*P.WSA&‘}, {M1}, {M2}, {M5}, {M6}, {M7}, {M13}.(19 independent elements)In revised system B (per Message 187) this would be written:P.Al, P.BW, P.Da, P.LF, P.Pi,P.Tr, P.WeC, P.Wo, P.WSA, M1, M2, M5, M6, M7, M13, M-, M+(17 independent elements)But you take issue with M+ and M- : Your call, but now you are stuck with system A to make your elements independent. I'll simplify the notation a little in the following discussion:P.(A) appears and is not affected: *P.(A)&‘ = element 1
P.(A) appears and becomes positively affected: *P.P(A)&+ = element 2
P.(A) appears and becomes negatively affected: *P.P(A)&- = element 3and a total of 51 independent elements plus one for "something else" (MSE) But you know who they are to assign +/- and therefore they are identified\observed.Again, from Message 166 we have: E2: Elements are observed, either singly or in combinations and all with possible repeated appearances -- P.Al, P.BeC, P.LF, P.Ri, P.WeC, P.Ya, M4, M5, P.BW-, P.Da-.In revised system A (per Message 187) this would be written: E2: Elements are observed, either singly or in combinations and all with possible repeated appearances -- {*P.Al&‘}, {*P.BeC&‘}, {*P.BW&P.BW-}, {*P.Da&P.Da-}, {*P.LF&‘}, {*P.Ri&‘}, {*P.WeC&‘}, {*P.Ya&‘}, {M4}, {M5}.Comparing E1 and E2 with list of all elements per modified system A: Notice that I have added the "something else" marker MSE to both events, as it could be present in any event and not have been recorded. What are those 6 possible transitions? I get 13 to 15Enjoy

Curiously I'm still trying to figure out how you develop a pattern, and I would think a simpler system would be the first approach, only making it more complicated when the simple pattern fails.In this case with generic M+ and M- I would think you would get more matches rather than less.Going back to my hypothetical episodes in Message 183: When I look at the "pattern" in Message 166 for event #15 I see it seems to me that I can make B15 be P.Da and then E is unique from A-C: So now if I change D2 and either D5 or D9 and then either D6 or D8...When I look at the "pattern" in Message 166 for events #2, 5, 8 and 9 I see It would appear that I can use P.Al or P.Ri or P.WeC, or M4 in the D2 position ... : I'll use P.Al for D2... that I can use P.Pi or P.Ri or M2 or M4 in the D5 position and leave D9 as P.Ya, or leave P.Ya in the D5 position and use P.Al or P.Pi or P.WeC or M1 or M2 or M4 or M11 or M14 in the D9 position ... : I'll use P.Pi for D5 and leave D9 as P.Ya... and that I can use P.Wo in the D6 position and leave M6 in the D8 position or leave M6 in the D6 position and use P.Pi or P.Ri or M1 or M5 or M13 in the D8 position ... : I'll leave M6 in D6 and use P.Ri for D8 So now I have 5 hypothetical episodes that fit your pattern ...... and the question is why should I think there is a pattern here --I do not see any equivalence between any elements in any one eventI do not see any pattern in the sequence of events for any episodeI do not see any sequence >2 elements in one episode that is repeated in any other episode (for example P.Ri comes after P.Al in episode A but before P.Al in episode C).There is no pattern here that I can see: what should I be seeing that I am missing?When you assemble mirrors and bits of colored plastic in a kaleidoscope you can create the appearance of colored patterns, where any one would be highly unlikely to occur, but the pattern is an artifact caused by the mirrors, not the colored plastic bits.Enjoy

P.Da M- P.Wo M+ or P.Wo M+ P.Da M- ... I don't see this as a problem Well isn't that a problem that applies to other instances -- your subjective evaluation of good/evil, based on your worldview? P.AEP M- M+ Curiously I think the pattern would be more universal: what I am trying to do is figure out is how you develop the pattern, so I figure a simpler system would be easier to start with.Enjoy