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Author Topic:   Some water measurements for the Flood
Minnemooseus
Member
Posts: 3945
From: Duluth, Minnesota, U.S. (West end of Lake Superior)
Joined: 11-11-2001
Member Rating: 10.0


Message 15 of 276 (729840)
06-19-2014 10:55 PM


Calculations of water depth if the Earth were a current sea level sphere
With the aid of Google and seemingly quite a bit of luck, I was able to track down a post of mine from 10+ years ago.
I calculated what the water depth would be if the solid part of the Earth were a sphere of the radius/diameter of the current sea level. In other words, I brought the ocean floor up to sea level and the continent level down to sea level.
Minnemooseus, in 2003, writes:
OK, I worked out the problem.
Earth diameter = 1.27x107 m, therefore radius = 6.35x107 m
The relative size of Earth, Jupiter, Sun (1 : 10 : 100)
Volume of the oceans = 1.3x109 km3 = 1.3x1018 m3
The average depth of the oceans = 2.5 miles = 4 km = 4000 m
Volume of Earth's Oceans - The Physics Factbook
Sphere volume = 4/3 Pi r3
I added the volume of the oceans to the calculated volume of the earth (by the way, the oceans volumes is only about 0.1 percent of the Earth's volume, so I was taking some liberties with significant figures).
Ramming that new sphere volume back through the sphere volume formula gave me a radius increase (sea level rise) of 2560 meters.
Source=Message 15 at the "Big-Sediment vs. Little-Sediment Flood Geology?" topic
So, if I got it right, if the Earth were a current sea level sphere, the water covering depth would be about 2560 meters.
Moose

Replies to this message:
 Message 16 by Faith, posted 06-19-2014 11:46 PM Minnemooseus has replied

  
Minnemooseus
Member
Posts: 3945
From: Duluth, Minnesota, U.S. (West end of Lake Superior)
Joined: 11-11-2001
Member Rating: 10.0


Message 17 of 276 (729843)
06-20-2014 1:08 AM
Reply to: Message 16 by Faith
06-19-2014 11:46 PM


Re: Calculations of water depth if the Earth were a current sea level sphere
I'm making the Earth a smooth sphere, with all surfaces the same elevation. The Earth radius/diameter is that which is the current sea level. I'm then distributing the volume of the oceans over this sphere. If my calculation were correct, then you would have a uniform water depth of about 2560 meters.
In other words, perfectly smooth continents and ocean basins, all at the same elevation, covered by 2560 meters of water.
In this approximation, you could then add mountains no higher that 2560 meters, if the water was to reach the mountain tops. 2560 meters is essentially nothing relative to the Earths radius - The solid surface is still essentially smooth.
Moose
Edited by Minnemooseus, : Add 3rd paragraph.

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Replies to this message:
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