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Author | Topic: Do you really understand the mathematics of evolution? | |||||||||||||||||||
Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
And you in the fish evolve into mammals clique think I have trouble with the english language.
Maybe the king can find the contact information by reading some fossil tea-leaves.PaulK writes: I could, but I don’t need it. She didn’t support your claim of cherry-picking and that’s all that needs to be said.Allison Zhang, Stanford University writes:
What do you think that "Make sure you’re comparing the same gene!" means ding-dong? I really hope you are only pretending to be a dummy.
The first thing to do is align the two DNA sequences together that you’re going to compare. Make sure you’re comparing the same gene!Kleinman writes:
I tried putting this sentence into Google Translate, it still comes out nonsense.
The king will now explain how fish evolve into mammals with frameshift mutations.PaulK writes: Poor Kleinman. He thinks that if we acknowledge that frameshift mutations - and indels that don’t shift the frame - we must assume that all evolutionary change is explained by frameshift mutations.Kleinman writes:
You have definitely proven your lack of qualifications in biology. From what you say here, it is also safe to assume that you have never been a math teacher. What I really suspect you are is an out of work comedian. You definitely have the qualifications for that. What really scares me is that I think PaulK actually was a biology teacher.PaulK writes: Well there’s your imagination running away with you again. I’ve never claimed any qualifications in biology and I’ve never worked as a teacher. Edited by Kleinman, : Typo
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: Oh, you have plenty of problems, but that’s not one on my list.
quote: Obviously you have to compare the same gene. Do you really think you can compare a gene taken from one species with a random chunk of DNA taken from another and get a decent phylogeny? You must be hoping that I am stupid enough to fall for these silly deceptions.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
OK, you are not pretending. So, according to Jukes-Cantor calculation, if you compare a single gene from two different species with a single base difference between them and a mutation rate of e-8, you get 50,000,000 generations separating the two species. So, ding-dong, what if you compare a collection of 10 equivalent genes at the same time, each with only a single base difference, that means 500,000,000 generations separating the two species. Now humans and chimps have more than 20,000 coding genes and very few exactly match. So, even if they differ by a single base at each coding genetic locus, you now have 20,000*50,000,000 generations separating the two species. And that is just 1.5% of the genome that you are comparing. Now, include the regulatory portion of the genome in your analysis which is a much larger portion of the genome. How many generations separating humans and chimpanzees? What do you think that "Make sure you’re comparing the same gene!" means ding-dong? I really hope you are only pretending to be a dummy.PaulK writes: Obviously you have to compare the same gene. Do you really think you can compare a gene taken from one species with a random chunk of DNA taken from another and get a decent phylogeny? You must be hoping that I am stupid enough to fall for these silly deceptions. Whatever problems I have in English pale to your problems in biology and mathematics.
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: No. According to the Jukes-Cantor calculation 3/4 of the bases should have changed in 50,000,000 generations. That’s going to be more than one. A lot more.
quote: Assuming that the genes were of roughly equal length it would mean that they agreed on the divergence time. Which would be well under. 50,000,000 generations. If you can handle the math, or even read the pages you cite you should know that much.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
So, when you said "I’ve never claimed any qualifications in biology", you are now claiming some qualifications? So, which 3/4ths of bases have changed and show us how you use that information for constructing a DNA phylogenetic tree. So, according to Jukes-Cantor calculation, if you compare a single gene from two different species with a single base difference between them and a mutation rate of e-8, you get 50,000,000 generations separating the two species.PaulK writes: No. According to the Jukes-Cantor calculation 3/4 of the bases should have changed in 50,000,000 generations. That’s going to be more than one. A lot more. You know PaulK, I'm actually learning something here!
Kleinman writes:
So, as the number of genes being analyzed increases and the number of genetic differences increases, the divergence time goes down. I'm impressed, you have just proven that your parents are bananas.
So, ding-dong, what if you compare a collection of 10 equivalent genes at the same time, each with only a single base difference, that means 500,000,000 generations separating the two speciesPaulK writes: Assuming that the genes were of roughly equal length it would mean that they agreed on the divergence time. Which would be well under. 50,000,000 generations.
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: I don’t claim any biology qualifications. But this is mathematics. And no, Jukes-Cantor won’t tell you which bases change as you ought to know.
quote: Wrong again. The divergence time is lower than your estimate because your estimate is hopelessly wrong. And since the divergence is based on the proportion of changed bases, it won’t change unless that proportion is changed.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
Are you now claiming some qualifications in mathematics? If so, show us the mathematics used to compute the divergence time if two sites are considered.
So, when you said "I’ve never claimed any qualifications in biology", you are now claiming some qualifications? So, which 3/4ths of bases have changed and show us how you use that information for constructing a DNA phylogenetic tree.PaulK writes: I don’t claim any biology qualifications. But this is mathematics. And no, Jukes-Cantor won’t tell you which bases change as you ought to know.Kleinman writes:
You just said, "Assuming that the genes were of roughly equal length it would mean that they agreed on the divergence time. Which would be well under. 50,000,000 generations." and now you are claiming qualifications in mathematics, show us the mathematics that it would be "well under. 50,000,000 generations".
So, as the number of genes being analyzed increases and the number of genetic differences increases, the divergence time goes down.PaulK writes: Wrong again. The divergence time is lower than your estimate because your estimate is hopelessly wrong. And since the divergence is based on the proportion of changed bases, it won’t change unless that proportion is changed.
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: No sensible person would use only two sites. You couldn’t get a usable estimate that way.
quote: I said that they would agree on the divergence time. I.e. each considered individually would give about the same divergence time. I also said that the divergence time would be well under 50,000,000 generations because only a small proportion of the bases has changed. In 50,000,000 generations 0.75 of the bases would be changed according to Jukes-Cantor with the given parameters.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
Do the math for any number of sites you think is sensible. And please show your math.
Are you now claiming some qualifications in mathematics? If so, show us the mathematics used to compute the divergence time if two sites are considered.PaulK writes: No sensible person would use only two sites. You couldn’t get a usable estimate that way.Kleinman writes:
So the divergence of two sites would give "about the same divergence time"? You just said, "No sensible person would use only two sites. You couldn’t get a usable estimate that way." Why can you get divergence times for one site or many sites but two sites is not sensible?
You just said, "Assuming that the genes were of roughly equal length it would mean that they agreed on the divergence time. Which would be well under. 50,000,000 generations." and now you are claiming qualifications in mathematics, show us the mathematics that it would be "well under. 50,000,000 generations".PaulK writes: I said that they would agree on the divergence time. I.e. each considered individually would give about the same divergence time.PaulK writes:
Then which sites do you use to determine DNA phylogenics? And how do you do the math since you now claim that you are qualified in that subject?
I also said that the divergence time would be well under 50,000,000 generations because only a small proportion of the bases has changed. In 50,000,000 generations 0.75 of the bases would be changed according to Jukes-Cantor with the given parameters.
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: Let’s start with some simpler math. When the Jukes-Cantor model reaches equilibrium, 3 quarters of the bases should have changed. If at that point only one base in the gene has changed, how many bases would you expect to be in the gene? And for a bonus biology question: could a gene be that length?
quote: Well let’s try some more simple mathematics. If one base in a gene 10,000 bases long has changed what proportion of bases has changed ? If you have two genes, each 10,000 bases long and one base in each has changed, what proportion of bases has changed? Are the two proportions different ?
quote: Because you aren’t just counting the sites that have changed, you’re also counting all the sites that haven’t. Which comes to a lot more than just two.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
Why couldn't all the bases have changed? After all, it is 50,000,000 generations. Can't some member of that population over 50,000,000 generations get a mutation at any site in the genome?
Do the math for any number of sites you think is sensible. And please show your math.PaulK writes: Let’s start with some simpler math. When the Jukes-Cantor model reaches equilibrium, 3 quarters of the bases should have changed.PaulK writes:
All I know from what you are explaining that only 3/4 of the sites in a gene have a mutation over 50,000,000 generations and 1/4 of the genome don't have a mutation. Why can't 1/4 of the gene not get a mutation?
If at that point only one base in the gene has changed, how many bases would you expect to be in the gene? And for a bonus biology question: could a gene be that length?Kleinman writes:
One would think the answer to that question depends on the mutation rate and the number of replications of that gene. But now you are telling us that 1/4 of that gene cannot have a mutation. Why is that?
So the divergence of two sites would give "about the same divergence time"?PaulK writes: Well let’s try some more simple mathematics. If one base in a gene 10,000 bases long has changed what proportion of bases has changed ?PaulK writes:
I thought you said that 3/4 of the bases have changed and 1/4 of the bases haven't changed. And now you are saying that 1 base has changed and 9,999 bases haven't changed. Is this what you mean by equilibrium?
If you have two genes, each 10,000 bases long and one base in each has changed, what proportion of bases has changed? Are the two proportions different ?Kleinman writes:
So, how many sites are changing, is it 1 or is it 7,500?
You just said, "No sensible person would use only two sites. You couldn’t get a usable estimate that way." Why can you get divergence times for one site or many sites but two sites is not sensible?PaulK writes: Because you aren’t just counting the sites that have changed, you’re also counting all the sites that haven’t. Which comes to a lot more than just two.
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PaulK Member Posts: 17886 Joined: Member Rating: 7.7 |
quote: Feel free to calculate the probability of that happening. 0.75^n where n is the number of bases.
quote: I’m sure you know that you claimed that only one base would change in a gene in 50,000,000 generations. So the expected length of the gene would be 1/0.75 bases. Let’s generously round up and say two. Not exactly plausible is it? And of course, if you really understood the mathematics you would know that already. So obviously you are either a fraud or a troll. And either way you need help.
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Kleinman writes:
So when n is very large, the probability of any base having a mutation goes to 0? Or are you saying that when n is large and after 50,000,000 generations, only 3/4ths of the bases can have a mutation?
Why couldn't all the bases have changed? After all, it is 50,000,000 generations. Can't some member of that population over 50,000,000 generations get a mutation at any site in the genome?PaulK writes: Feel free to calculate the probability of that happening. 0.75^n where n is the number of bases.Kleinman writes:
Did I say that? Could you please post the message number and quote where I said that? Why couldn't all the bases have changed? After all, it is 50,000,000 generations. Can't some member of that population over 50,000,000 generations get a mutation at any site in the genome?PaulK writes: I’m sure you know that you claimed that only one base would change in a gene in 50,000,000 generations. So the expected length of the gene would be 1/0.75 bases. Let’s generously round up and say two. Not exactly plausible is it? And of course, if you really understood the mathematics you would know that already. So obviously you are either a fraud or a troll. And either way you need help. And if I understand your math, you are claiming that the length of a gene is 1.5 times the number of bases in that gene which you generously round up to 2. This kind of math will not change your employment status as a comedian. And you have no idea how much you helped me!
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Kleinman Member (Idle past 528 days) Posts: 2142 From: United States Joined: |
Since PaulK seems to be having a bit of trouble understanding the Jukes-Cantor model, here's a simple explanation of what this model is all about. It is nothing more than a variation of the same calculation Taq did at the beginning of this thread. When the Jukes-Cantor model reaches equilibrium is essentially the same as when 3e9 replications have occurred (for a mutation rate of e-9) so that on average, one of every possible substitution has occurred.
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