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math simplification problem

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Author Topic:   math simplification problem
er
Inactive Member

er Posts Only
Message 1 of 6 (51088)
08-19-2003 12:00 PM

i dont know what exactly to do with this, my friend just asked me to solve this for her:
-y5(r+w)-y6(z+k)
the 5 and the 6 are powers (i mean -y5 means negative y raised to 5)
hoping for a reply thanks
Replies to this message:
 Message 2 by crashfrog, posted 08-19-2003 12:12 PM er has not replied
 Message 3 by Percy, posted 08-19-2003 12:17 PM er has not replied
  
crashfrog
Member (Idle past 1486 days)
Posts: 19762
From: Silver Spring, MD
Joined: 03-20-2003

crashfrog Posts Only
Message 2 of 6 (51093)
08-19-2003 12:12 PM 		Reply to: Message 1 by er
08-19-2003 12:00 PM

Solve it for what? You can't solve an expression, can you?
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 Message 1 by er, posted 08-19-2003 12:00 PM er has not replied
  
Percy
Member
Posts: 22475
From: New Hampshire
Joined: 12-23-2000
Member Rating: 4.7

Percy Posts Only
Message 3 of 6 (51096)
08-19-2003 12:17 PM 		Reply to: Message 1 by er
08-19-2003 12:00 PM

You can't solve it without a relationship. Did you mean this:
​
-y5(r+w)-y6(z+k) = 0
​
I assume you want to solve for y in terms of k, r, w and z.
​
Solving:
​
(r+w)+y(z+k) = 0
y(z+k) = -(r+w)
y = -(r+w)/(z+k)
​
--Percy
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 Message 1 by er, posted 08-19-2003 12:00 PM er has not replied
Replies to this message:
 Message 4 by Mike Holland, posted 08-21-2003 8:13 AM Percy has replied
  
Mike Holland
Member (Idle past 502 days)
Posts: 179
From: Sydney, NSW,Auistralia
Joined: 08-30-2002

Mike Holland Posts Only
Message 4 of 6 (51479)
08-21-2003 8:13 AM 		Reply to: Message 3 by Percy
08-19-2003 12:17 PM

Sorry, Percy, but you slipped up when you divided by y5, and missed the possible solution y=0.
Mike Holland.
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 Message 3 by Percy, posted 08-19-2003 12:17 PM Percy has replied
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Percy
Member
Posts: 22475
From: New Hampshire
Joined: 12-23-2000
Member Rating: 4.7

Percy Posts Only
Message 5 of 6 (51488)
08-21-2003 9:43 AM 		Reply to: Message 4 by Mike Holland
08-21-2003 8:13 AM

Oops! Trying again:
​
-y5(r+w)-y6(z+k) = 0
-y5((r+w)+y(z+k)) = 0
-y5 = 0; (r+w)+y(z+k) = 0
y = 0; y(z+k) = -(r+w)
y = 0, -(r+w)/(z+k)
​
But I fear our thread originator is long gone.
​
--Percy
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Replies to this message:
 Message 6 by jennilee, posted 11-17-2003 10:20 PM Percy has not replied
  
jennilee
Inactive Member

jennilee Posts Only
Message 6 of 6 (67253)
11-17-2003 10:20 PM 		Reply to: Message 5 by Percy
08-21-2003 9:43 AM

Just checking to see if my post works.
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