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Member (Idle past 1721 days) Posts: 19762 From: Silver Spring, MD Joined: |
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Author | Topic: For Inquisitor, et al: What is Evolution? | |||||||||||||||||||||||
Buzsaw Inactive Member |
quote: Rock is about three times more dense than water, but 70% of the earth's surface is ocean. My understanding is that the average thickness of the earth's crust is about three miles whereas the average thickness of the continents is about twenty miles. When the flood came, the thin crust would've sank into the molten core of the earth by the huge volumn of water, pushing up the continents from the displacement of the molten core which would rise forming the mountain ranges and cooling. The volumn of the water would overcome the density of the rock, imo.
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crashfrog Member (Idle past 1721 days) Posts: 19762 From: Silver Spring, MD Joined: |
No, you got it exactly right: If I have 4 darts, each has a probability of only 1/4 of hitting...10 darts means each has only a 1/10 probability of hitting...an infinite number of darts means each has an infinitesimal probability of hitting. And, indeed, a single dart means there is a guaranteed chance of hitting. But, the question put before us is to determine a solution for all possible cases. What I don't understand is - are these hypothetical darts whose accuracy decreases as the number of them increases, or do you believe this to be fundamental property of real-life darts? I realize this is nit-picking, but I'm curious. Given n darts, each with a constant chance of hitting the target, the chances of all of them not hitting the target decreases as n increases. Is that what you're after?
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NosyNed Member Posts: 9012 From: Canada Joined: |
You're way off topic here. How about going over to the flood and explain how you can pile water up on something to make it push down on it.
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Admin Director Posts: 13107 From: EvC Forum Joined: |
Hello, everyone, remember me? For Inquisitor, et al: What is Evolution? I'm getting lonely!
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crashfrog Member (Idle past 1721 days) Posts: 19762 From: Silver Spring, MD Joined: |
Looks like Inquisitor is gone. Perhaps the topic should close? I think there's already other topics for some of the disputes we've spawned here.
No one who has an actual question about the theory has posted. I guess it's done, then?
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zephyr Member (Idle past 4804 days) Posts: 821 From: FOB Taji, Iraq Joined: |
I was expecting that. I'd vote for closing it. Not sure how democratic it really is though so do your worst!
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Coragyps Member (Idle past 988 days) Posts: 5553 From: Snyder, Texas, USA Joined: |
So six miled of water with a density of 1 kg/L is going to push 20 - 3 = 17 miles of rock with a density of 3 kg/L upwards. Try that in your kitchen, and get back to us on how much uplift you get. And keep in mind that you are starting with rock, not air, in your seabeds-to-be.
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NosyNed Member Posts: 9012 From: Canada Joined: |
I'd say close it to new posts until someone wants to ask the question again.
It was my thought originally that it would act as a place to refer to rather than go through the whole mess each time someone asks.
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Rrhain Member (Idle past 261 days) Posts: 6351 From: San Diego, CA, USA Joined: |
crashfrog responds to me:
quote:quote: Hypothetical darts. It's a thought experiment designed to see how well people who make arguments of probability can calculate a simple probability. I don't think you could come up with an actual infinite number of darts. But then again, that was the last part of the question: How many darts must you have to be within 99% of the value of an infinite number of darts? While we can't get an infinite number of darts, we can get arbitrarily close to that value with a finite number of darts.
quote: S'aright. You'd want to be sure you understand the questiion before answering it.
quote: Not just a constant chance, but a specific chance.
quote: That's a general result, yes, but I'm looking for the specific answer with all work shown. Does the chance of them all not hitting decrease without limit or not? That's why I asked the questions that I did: Suppose I have n darts, each with a 1/n chance of striking the target. What is the probability of hitting the target at least once given 10 darts? 20 darts? An infinite number of darts? How many darts must you have to be within 99% of the value of an infinite number of darts? ------------------Rrhain WWJD? JWRTFM!
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Vunderkind Guest |
quote: Why don't you ask a Statistics Professor? Sheesh. Crashfrog is no stats professor; he's a moron, and clearly not an individual with more than a High School diploma. But anyway, please post the answer, as I want to take it next door to my neighbor who happens to be a Stats Prof. at a major accredited university boasting of over 47,000 FULL-TIME enrollment!!! Interesting that I even took two of his stats classes. And not once in this thread have I seen any argument come close to containing the language consisent with that of Statistical Analysis I heard in my stats classes. What's more puzzling, is that the same arguments are too independantly simple to be of any advanced merit within the stats' field. As if one could answer statistics with philosophy, or is it so unclear philosophy is not statistics? The bell tolls here even for knot-it-all John. (let the typo "knot" remain as it unwittingly, but appropriately, revealed the philosophical knot John has tied himself up with). It's a true circle jerk here. Time to close the thread Admin-mommy. Nevertheless, I can't wait to print this thread out and show it to my neighbor. Y'all just might spontaneously create a creationist by the utter incoherent foolishness of your arguments. But how one is to weave such a hopeful monster into the ToE is the question... Good day, mates!
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Mister Pamboli Member (Idle past 7831 days) Posts: 634 From: Washington, USA Joined: |
quote:Why? Do you think the question is such that only an advanced statistican could answer it? No shame on crashfrog, in that case. quote:If he exists, he has my deepest sympathy. quote:Then why don't you post the answer? Were you not paying attention during your neighbour's classes? Or is the question such that only an advanded statistician could answer it? Perhaps by took his stats classes you mean that you found his lecture notes when scavenging in his trash? quote:Ah, so you did attend them? Still, hearing is not understanding, dear child. quote:My, my: quite the independant mind, if not very consisent. quote:You should do so, next time you climb the hill from your trailer park to clean his pool. And do ask him to join the forum so we can read his reply.
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Quetzal Member (Idle past 6126 days) Posts: 3228 Joined: |
And another unregistered drive-by poster decides to pop in and dispense gratuitous insults in an unsubstantive post. I wonder what it is about Springtime in the Northern Hemisphere? Must be something to do with new sap flowing, sun shining, birds singing, slimy larvae crawling out from under rocks...
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Admin Director Posts: 13107 From: EvC Forum Joined: |
This is the "Welcome, Vistors!" forum, not the "Free For All" forum.
Vunderkind, I'm sorry this thread isn't to your liking, but we *do* have Forum Guidelines that members are expected to follow. I know you're not registered yet, but you can still be banned, so please follow the guidelines. Others, please don't respond in kind when you encounter posts of this nature. --------------------EvC Forum Administrator |
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Percy Member Posts: 22947 From: New Hampshire Joined: Member Rating: 7.0 |
Rrhain writes: Suppose I have n darts, each with a 1/n chance of striking the target. What is the probability of hitting the target at least once given 10 darts? 20 darts? An infinite number of darts? How many darts must you have to be within 99% of the value of an infinite number of darts? Just noticed this statistics problem for the first time, I'll give it a shot. Here's the general solution for n, just do the math to find the answers for 10, 20 and ∞ darts:
Pn = 1 - (1 - 1/n)n To find how many darts you must have to be within 99% of the value for ∞ darts, simply solve this equation for n:
Pn - P∞ = .01 (1 - (1 - 1/n)n) - (1 - (1 - 1/∞)∞) = .01 The term for ∞ goes to 0, so this becomes simply:
(1 - (1 - 1/n)n) = .01 That's the answer, but I don't know how to solve the equation. --Percy
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crashfrog Member (Idle past 1721 days) Posts: 19762 From: Silver Spring, MD Joined: |
Come to think of it, weren't we closing this thread?
Inquisitor has stopped inquisiting. All we have now is Buzsaw coming up with value-laden misstatements of the ToE. Maybe we could give this a day or two for the probability aspect to be resolved but I'd say we're about done after that...
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